How do you compute the derivative of #y=(sin^-1)x# and x=3/5? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Trevor Ryan. Oct 16, 2015 #2# Explanation: #d/dxsin^(-1)x=1/(sqrt(1-x^2))# #thereforedy/dx|_(x=3/5)=1/(sqrt(1-(3/5)^2))=2# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1448 views around the world You can reuse this answer Creative Commons License