Question

How do you condense `[1 - 5log_3x]/2`?

Answer 1

`log_3 (3/x^5)^(1/2) " or " log_3 sqrt(3/x^5)`

Explanation:

I assume that "condense" means "write as a single logarithm of a single expression". (I assume that because that's what I mean when I tell students to condense such an expression.)

`[1 - 5log_3x]/2 = 1/2(1-5log_3 x)`

`= 1/2 (1-log_3 x^5)`

`= 1/2 (log_3 3 - log_3 x^5)`

`= 1/2 log_3 (3/x^5)`

`= log_3 (3/x^5)^(1/2) " or " log_3 sqrt(3/x^5)`