How do you condense log_10 x - 4log_10 y?
1 Answer
Apr 16, 2018
Explanation:
"using the "color(blue)"laws of logarithms"
•color(white)(x)logx^nhArrnlogx
rArr4log_(10)y=log_(10)y^4
•color(white)(x)logx-logyhArrlog(x/y)
rArrlog_(10)x-log_(10)y^4=log_(10)(x/y^4)