How do you convert #(0,2)# from cartesian to polar coordinates?

2 Answers
Jul 10, 2017

#(2, pi/2)#

Explanation:

A polar coordinate is in the form #(r, theta)#, where #r# is the distance from the origin and #theta# is the corresponding angle. We can see here that #r=2# and #theta=pi/2#. However, we can also use the following formulas:

#r^2=x^2+y^2#

#tan theta = y/x#

#r^2=x^2+y^2#
#r=sqrt(x^2+y^2)#
#r=sqrt(0^2+2^2)#
#r=2#

#tan theta = 2/0#
This is undefined, but #tan (pi/2)# is undefined anyways.

The polar coordinate is #(2, pi/2)#.

Jul 10, 2017

#(2,pi/2)#

Explanation:

#"to convert from "color(blue)"cartesian to polar"#

#"that is " (x,y)to(r,theta)" where"#

#•color(white)(x)r=sqrt(x^2+y^2)#

#•color(white)(x)theta=tan^-1(y/x)color(white)(x);-pi< theta<= pi#

#"here " x=0" and " y=2#

#rArrr=sqrt(0^2+2^2)=2#

#theta=tan^-1(2/0)larrcolor(red)" undefined"#

#rArrtheta=pi/2#

#rArr(0,2)to(2,pi/2)#