How do you convert $(- 1, 405^{\circ})$ $(-1, 405^circ)$ from polar to cartesian coordinates?

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How do you convert $(- 1, 405^{\circ})$ $(-1, 405^circ)$ from polar to cartesian coordinates?

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Answer 1 · 2018-04-26T08:16:15

$(- \frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2})$ $(-sqrt2/2,-sqrt2/2)$

Explanation:

$(r, θ) \to (x, y) \Rightarrow (r cos θ, r sin θ)$ $(r,theta)->(x,y)=>(rcostheta,rsintheta)$

$(r, θ) = (- 1, 405^{\circ})$ $(r,theta)=(-1,405^circ)$
$(x, y) = (- cos (405), - sin (405)) = (- \frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2})$ $(x,y)=(-cos(405),-sin(405))=(-sqrt2/2,-sqrt2/2)$

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How do you convert $(- 1, 405^{\circ})$ $(-1, 405^circ)$ from polar to cartesian coordinates?

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How do you convert (−1,405∘)(-1, 405^circ) from polar to cartesian coordinates?

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How do you convert $(- 1, 405^{\circ})$ $(-1, 405^circ)$ from polar to cartesian coordinates?