How do you convert #(2, (11pi)/6)# from polar to cartesian coordinates?
1 Answer
Aug 29, 2017
Explanation:
#x = r cos theta#
#y = r sin theta#
In this case,
#x = 2 cos ((11pi)/6) = 2 * sqrt3/2 = sqrt3#
#y = 2 sin ((11pi)/6) = 2 * -1/2 = -1#
The Cartesian coordinate is