Question

How do you convert `(3, 2pi/3)` into rectangular forms?

Answer 1

polar form: `(3,(2pi)/3) rarr` rectangular form: `(-3/2,(3sqrt(3))/2)`

Explanation:

Given `(r,theta) = (3,(2pi)/3)`

`x= r*cos(theta) = 3*cos((2pi)/3) = 3*(-1/2) = -3/2`

`y = r*sin(theta)=3*sin((2pi)/3) = 3*(sqrt(3)/2) = (3sqrt(3))/2`