Question

How do you convert `( 3x , -3y )` into polar coordinates?

Answer 1

`3sqrt(x^2+y^2)/_tan^(-1)(-y/x)`

Explanation:

`r=sqrt((3x)^2+(-3y)^2)=sqrt(9(x^2+y^2))=3sqrt(x^2+y^2)`

`theta=tan^(-1)((-3y)/(3x))=tan^(-1)(-y/x)`

Therefore the polar co-ordinates are `3sqrt(x^2+y^2)/_tan^(-1)(-y/x)`