How do you convert #(-4,pi/6)# into rectangular coordinates?

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Answer 1 · 2016-02-25T09:30:34

#x=-2sqrt3# and #y=-2#

To convert the polar coordinate #(-4, pi/6)# to rectangular coordinates, you have to use the following

#x=r cos theta# and #y=r sin theta#

given #r=-4# and #theta=pi/6#

#x=r cos theta=-4 *cos (pi/6)=-4*sqrt3/2=-2sqrt3#

#y=r sin theta=-4* sin (pi/6)=-4*(1/2)=-2#

God bless you...I hope my explanation helps...