How do you convert $(6, 90^{\circ})$ $(6, 90^circ)$ from polar to cartesian coordinates?

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Answer 1 · 2017-03-18T16:44:23

The rectangular coordinates are $(6, 0)$ $(6,0)$

To convert from polar coordinates $(r, θ)$ $(r, theta)$ to rectangular coordinates $(x, y)$ $(x,y)$ , we apply the following equations

$x = r cos θ$ $x=rcostheta$

$y = r sin θ$ $y=rsintheta$

Here, $(r,theta)=(6,90º)$

$sin90º=1$

$cos90º=0$

Therefore,

$x=6sin90º=6$

$y=6cos90º=0$

So,

The rectangular coordinates are $(6,0)$

How do you convert (6, 90^circ)(6,90∘)(6, 90^circ) from polar to cartesian coordinates?