How do you convert #(6, pi/4)# into rectangular coordinates? Precalculus Polar Coordinates Converting Coordinates from Polar to Rectangular 1 Answer sankarankalyanam Jul 9, 2018 #color(purple)((x,y) = (3 sqrt2, 3sqrt2) " or " (4.2426, 4.2426)# Explanation: #"Given " (r, theta) = (6, pi/4)# #x = r cos theta = 6 * cos (pi/4) = 6 / sqrt2 = 3 sqrt 2 ~~ 4.2426# #y = r sin theta = 6 * sin (pi/4) = 6 / sqrt2 = 3 sqrt 2 ~~ 4.2426# Answer link Related questions What is the formula for converting polar coordinates to rectangular coordinates? How do I convert polar coordinates #(5, 30^circ)# to rectangular coordinates? How do I convert polar coordinates #(3.6, 56.31)# to rectangular coordinates? How do I convert polar coordinates #(10, -pi/4)# to rectangular coordinates? How do I convert polar coordinates #(4,-pi/3)# to rectangular coordinates? How do I convert polar coordinates #(6, 60^circ)# to rectangular coordinates? How do I convert polar coordinates #(-4, 230^circ)# to rectangular coordinates? What is the Cartesian equivalent of polar coordinates #(sqrt97, 66^circ)#? What is the Cartesian equivalent of polar coordinates #(2, pi/6)#? What is the Cartesian equivalent of polar coordinates #(7, pi)#? See all questions in Converting Coordinates from Polar to Rectangular Impact of this question 3491 views around the world You can reuse this answer Creative Commons License