How do you convert # (8, pi/2)# into rectangular coordinates? Precalculus Polar Coordinates Converting Coordinates from Polar to Rectangular 1 Answer sankarankalyanam Jul 9, 2018 #color(purple)(x = 0, y = 8# Explanation: #r, theta = 8, pi/2# #x = r cos theta = 8 * cos (pi/2) = 0# #y = r sin theta = 8 * sin (pi/2) = 8# Answer link Related questions What is the formula for converting polar coordinates to rectangular coordinates? How do I convert polar coordinates #(5, 30^circ)# to rectangular coordinates? How do I convert polar coordinates #(3.6, 56.31)# to rectangular coordinates? How do I convert polar coordinates #(10, -pi/4)# to rectangular coordinates? How do I convert polar coordinates #(4,-pi/3)# to rectangular coordinates? How do I convert polar coordinates #(6, 60^circ)# to rectangular coordinates? How do I convert polar coordinates #(-4, 230^circ)# to rectangular coordinates? What is the Cartesian equivalent of polar coordinates #(sqrt97, 66^circ)#? What is the Cartesian equivalent of polar coordinates #(2, pi/6)#? What is the Cartesian equivalent of polar coordinates #(7, pi)#? See all questions in Converting Coordinates from Polar to Rectangular Impact of this question 2999 views around the world You can reuse this answer Creative Commons License