How do you convert ${log}_{3} 29$ $log_(3) 29$ to a natural logarithm?

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Answer 1 · 2015-09-06T23:20:15

You should: get $\frac{ln 29}{ln 3}$ $ln29/ln3$

You can use the Change of Base formula to get:
${log}_{3} (29) = \frac{ln 29}{ln 3}$ $log_3(29)=ln29/ln3$
where $ln$ $ln$ represents the natural log.

How do you convert log_(3) 29log329log_(3) 29 to a natural logarithm?