How do you convert the rectangular coordinate $(1,-sqrt3)$ into polar coordinates?

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Answer 1 · 2018-03-08T02:29:18

$rec(1,-sqrt3)=$ $pol(2,-pi/3)$ in radians or $pol(2,-60^@)$ in degrees

Polar in in the form $(r,theta)$

$r=sqrt(x^2+y^2)$

and

$theta=tan^-1(y/x)$

$:.$ $(r, theta)=$ $(sqrt(1^2+(-sqrt(3))),tan^-1((-sqrt(3))/1))$

$=(sqrt(4),-pi/3)$

$=(2,-pi/3)$

Convert radians to degrees by $180/pi$

$=(2,-cancel(pi)/3*180/cancel(pi))$

$=(2,-180/3)$

$=(2,-60^@)$

$=(2,300^@)$

How do you convert the rectangular coordinate (1,-sqrt3)(1,-sqrt3) into polar coordinates?