How do you convert the rectangular coordinate $(- 8, 0)$ $(-8,0)$ into polar coordinates?

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Answer 1 · 2017-06-08T15:12:46

$8 (cos π + i sin π)$ $8 (cos pi + i sin pi)$

$r^{2} = x^{2} + y^{2} \Rightarrow r = 8$ $r^2 = x^2 + y^2 => r = 8$

$tan θ = \frac{y}{x} = 0 \Rightarrow θ = k π$ $tan theta = y/x = 0 => theta = k pi$

How do you convert the rectangular coordinate (−8,0)(-8,0) into polar coordinates?