How do you decide whether the relation #x^2 + y^2 = 25# defines a function?

1 Answer
Nov 1, 2015

A relation is a function if for every #x# there is (at most) one #y#.
A function can be seen as a recipe, saying if #x# is such, then #y# is so.

Explanation:

In this case the relation can be rewritten as
#y^2=25-x^2->y=+sqrt(25-x^2)ory=-sqrt(25-x^2)#

These values are only defined in the domain #-5<=x<=5#, but that's not important here:

For the #x#'s in the domain there are always TWO #y#'s (except when #x=-5orx=5#)

Extra:
This relation defines a circle with centre #(0,0)# and radius #sqrt25=5#