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How do you determine if $y = 0.4 {(\frac{1}{3})}^{x}$ $y=0.4(1/3)^x$ is an exponential growth or decay?

1 Answer

Mar 30, 2017

$y = 0.4 {(\frac{1}{3})}^{x}$ $y=0.4(1/3)^x$ is an exponential decay

Explanation:

Since $(\frac{1}{3}) \in (0, 1)$ $(1/3) in (0,1)$

as $x \to \infty$ $xrarr oo$
$XXX {(\frac{1}{3})}^{x} \to 0$ $color(white)("XXX")(1/3)^x rarr 0$

and if ${(\frac{1}{3})}^{x} \to 0$ $(1/3)^x rarr 0$
then
$XXX$ $color(white)("XXX")$ so does $0.4 {(\frac{1}{3})}^{x}$ $0.4(1/3)^x$

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