How do you determine whether #triangle ABC# has no, one, or two solutions given #A=52^circ, a=9, b=20#?

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Answer 1 · 2018-06-21T07:16:14

#color(crimson)("As "sin B " can have a value only between " -1 " & "+1#,

#color(blue)("Given sum doesn't have a solution"#

![https://sites.google.com/site/trigingwithstarr/law-of-sines-and-cosines]( useruploads.socratic.org )

#hat A = 52^@, a = 9, b = 20#

Applying Law of Sines,

#a / sin A = b / sin B = c / sin C#

#sin B = (b sin A ) / a = (20 * sin 52 ) / 9 = 1.7511#

#"As "sin B " can have a value only between " -1 " & "+1#,

#"Given sum doesn't have a solution"#