How do you differentiate $2 cos (x) + {cos}^{2} (x)$ $2cos(x)+cos^2(x)$ ?

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How do you differentiate $2 cos (x) + {cos}^{2} (x)$ $2cos(x)+cos^2(x)$ ?

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Answer 1 · 2017-04-11T18:24:57

$- 2 sin x - sin 2 x$ $-2sinx-sin2x$

Explanation:

$\frac{d}{d x} (2 cos x + {cos}^{2} x)$ $d/dx(2cosx+cos^2x)$
$" "$
$= \frac{d}{d x} (2 cos x) + \frac{d}{d x} ({cos}^{2} x)$ $=d/dx(2cosx)+d/dx(cos^2x)$
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$= 2 (\frac{d}{d x} (cos x)) + 2 {cos}^{2 - 1} x (\frac{d}{d x} (cos x))$ $=2(d/dx(cosx))+2cos^(2-1)x(d/dx(cosx))$
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$= 2 (- sin x) + 2 cos x (- sin x)$ $=2(-sinx)+2cosx(-sinx)$
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$= - 2 sin x - 2 cos x sin x$ $=-2sinx-2cosxsinx$
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$= - 2 sin x - sin 2 x$ $=-2sinx-sin2x$

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How do you differentiate $2 cos (x) + {cos}^{2} (x)$ $2cos(x)+cos^2(x)$ ?

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How do you differentiate $2 cos (x) + {cos}^{2} (x)$ $2cos(x)+cos^2(x)$ ?