How do you differentiate #cos 2x#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Noah G Jan 3, 2017 Use the chain rule. We let #y = cosu# and #u = 2x#. Then #dy/(du) = -sinu# and #(du)/dx= 2#. #dy/dx = dy/(du) xx (du)/dx# #dy/dx = -sinu xx 2# #dy/dx = -2sinu# Since #u = 2x#: #dy/dx = -2sin2x# Hopefully this helps! Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 8015 views around the world You can reuse this answer Creative Commons License