How do you differentiate $f(x)=(2x^3+3)cosx^2$ ?

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Answer 1 · 2017-06-07T19:56:30

$D_x f(x) = 6x^2 cos x^2 - (4x^3 + 6) x sin x^2$

$D_x f = D_x (2x^3 + 3) cos x^2 + (2x^3 + 3) D_x cos x^2$

$D_x f = 6x^2 cos x^2 + (2x^3 + 3) (-sin x^2) D_x x^2$

How do you differentiate f(x)=(2x^3+3)cosx^2f(x)=(2x^3+3)cosx^2?