Question

How do you differentiate `f(x)=(2x^3+3)cosx^2`?

Answer 1

`D_x f(x) = 6x^2 cos x^2 - (4x^3 + 6) x sin x^2`

Explanation:

`D_x f = D_x (2x^3 + 3) cos x^2 + (2x^3 + 3) D_x cos x^2`

`D_x f = 6x^2 cos x^2 + (2x^3 + 3) (-sin x^2) D_x x^2`