Question

How do you differentiate `f(x)=(2x+3)/6` using the quotient rule?

Answer 1

here

Explanation:

using the formula `f(x)= (h(x))/g(x)`

`f'(x)=[g(x)*h'(x) - h(x)* g'(x)]/(g(x))^2`

`f'(x)=((6)*(2)-(2x+3)*0)/36= 12/36=2/6=1/3`