How do you differentiate #f(x) = sin (cos(3x -2)) #?

1 Answer
May 25, 2018

#f'(x)=-3cos(cos(3x-2))sin(3x-2)#

Explanation:

#f(x) = sin (cos(3x -2))#

Differentiate,

#f'(x)=cos(cos(3x-2))(d/dx(cos(3x-2)))#

Differentiate,

#f'(x)=cos(cos(3x-2))(-sin(3x-2))(d/dx(3x-2))#

Differentiate,

#f'(x)=cos(cos(3x-2))(-sin(3x-2))(3)#

Simplify,

#f'(x)=-3cos(cos(3x-2))sin(3x-2)#