How do you differentiate $f (x) = sin (cos (3 x - 2))$ $f(x) = sin (cos(3x -2))$ ?

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Answer 1 · 2018-05-25T13:30:03

$f'(x)=-3cos(cos(3x-2))sin(3x-2)$

$f(x) = sin (cos(3x -2))$

Differentiate,

$f'(x)=cos(cos(3x-2))(d/dx(cos(3x-2)))$

Differentiate,

$f'(x)=cos(cos(3x-2))(-sin(3x-2))(d/dx(3x-2))$

Differentiate,

$f'(x)=cos(cos(3x-2))(-sin(3x-2))(3)$

Simplify,

$f'(x)=-3cos(cos(3x-2))sin(3x-2)$

How do you differentiate f(x) = sin (cos(3x -2)) f(x)=sin(cos(3x−2))f(x) = sin (cos(3x -2)) ?