How do you differentiate $f (x) = sin (cos 3 x) - sin x cos 3 x$ $f(x) = sin (cos3x) - sinxcos3x$ ?

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Answer 1 · 2015-05-04T15:40:23

The differential would be -3sin3x cos(cos3x) - cosx cos3x +3 sin3x sinx

f'(x)= $\frac{d}{d x} sin (cos 3 x) - \frac{d}{d x} (sin x cos 3 x)$ $d/dx sin(cos3x)- d/dx(sinx cos3x)$

= cos(cos3x)*3(-sin3x) - (cosx cos3x-3sin3x sinx)

= -3sin3x cos(cos3x) - cosx cos3x +3 sin3x sinx

How do you differentiate f(x)=sin(cos3x)−sinxcos3xf(x) = sin (cos3x) - sinxcos3x?