How do you differentiate f(x) = tan^2(3x) ? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Sridhar V. Mar 26, 2018 If " f(x) = "tan^2(3x), then color(blue)((d)/(dx) f(x) = f'(x)=6 sec^2 (3x) * tan (3x) Explanation: Given: f(x) = "tan^2(3x) We can write this function as f(x) = "tan(3x)^2 d/(dx) tan(3x)^2 rArr 2 tan (3x) (d/dx) tan (3x) rArr 2 *tan (3x) *Sec^2 (3x)*3 rArr 6*sec^2(3x)*tan(3x) Hence, color(blue)((d)/(dx) f(x) = f'(x)= "6 sec^2 (3x) * tan (3x) Answer link Related questions What is the derivative of y=cos(x) ? What is the derivative of y=tan(x) ? How do you find the 108th derivative of y=cos(x) ? How do you find the derivative of y=cos(x) from first principle? How do you find the derivative of y=cos(x^2) ? How do you find the derivative of y=e^x cos(x) ? How do you find the derivative of y=x^cos(x)? How do you find the second derivative of y=cos(x^2) ? How do you find the 50th derivative of y=cos(x) ? How do you find the derivative of y=cos(x^2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2585 views around the world You can reuse this answer Creative Commons License