How do you differentiate $f (x) = x^{3} tan x$ $f(x)=x^3tanx$ ?

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Answer 1 · 2016-12-22T18:20:48

$3 x^{2} tan x + x^{3} {sec}^{2} x$ $3x^2 tan x +x^3 sec^2x$

Apply product rule of differentiation,

$\frac{{d x}^{3}}{d x} tan x + x^{3} \frac{d}{d x} tan x$ $dx^3 /dx tan x + x^3 d/dx tanx$

= $3 x^{2} tan x + x^{3} {sec}^{2} x$ $3x^2 tan x +x^3 sec^2x$

How do you differentiate f(x)=x3tanxf(x)=x^3tanx?