How do you differentiate #F(x) = (x)arctan x - (Ln ((x^2)+1))/2#?
1 Answer
May 7, 2017
Explanation:
We have to use the product rule on
#F'(x)=(d/dxx)arctanx+x(d/dxarctanx)-1/2(1/(x^2+1))(d/dx(x^2+1))#
#F'(x)=arctanx+x(1/(1+x^2))-1/2(1/(1+x^2))(2x)#
#F'(x)=arctanx+x/(1+x^2)-x/(1+x^2)#
#F'(x)=arctanx#