How do you differentiate $g = \frac{3 + tan x}{x}$ $g = (3 + tanx) / x$ ?

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Answer 1 · 2015-06-23T18:24:08

$\frac{x {sec}^{2} x - (3 + tan x)}{x^{2}}$ $(x sec^2x -(3+tanx)) /x^2$

Apply quotient rule to get the derivative as $\frac{x {sec}^{2} x - (3 + tan x)}{x^{2}}$ $(x sec^2x -(3+tanx)) /x^2$

How do you differentiate g = (3 + tanx) / xg=3+tanxxg = (3 + tanx) / x?