Question

How do you differentiate `g(x)= (2x)/(x-1)`?

Answer 1

`(-2)/(x-1)^2`

Explanation:

We know that,
`color(red)(d/(dx)(u/v)=(v*u^'-u*v^"')/v^2)`
`y=(2x)/(x-1)=>(dy)/(dx)=((x-1)(2)-(2x)(1))/(x-1)^2`
`(dy)/(dx)=(cancel(2x)-2-cancel(2x))/(x-1)^2=(-2)/(x-1)^2`