How do you differentiate ${ln x}^{\frac{1}{2}}$ $lnx^(1/2)$ ?

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Answer 1 · 2016-03-06T16:56:44

You can do it like this:

$f (x) = {ln x}^{\frac{1}{2}}$ $f(x)=lnx^(1/2)$

$:.f(x)=(lnx)/(2)$

$:.f'(x)=(1/x)/(2)=1/(2x)$

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