Question

How do you differentiate `s=(1+sint)/(1+tant)`?

Answer 1

`s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2`

Explanation:

`s=(1+sint)/(1+tant)=u/v`

`s'=(vu'-uv')/v^2`

`u=1+sint`
`u'=cost`

`v=1+tant`
`v'=sec^2t`

`s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2`