Question

How do you differentiate `y=(8x^3-6x^2-4)/(2x^2)`?

Answer 1

`y'=4+ 4/x^3`

Explanation:

re- write `y=(8x^3-6x^2-4)/(2x^2)` as

`y=4x-3-2/x^2`

and apply the power rule `d/dx (x^n) = n x ^ (n-1)`

to get

`y'=4+ 4/x^3`