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How do you differentiate $y = {cos}^{2} (x^{2} - 3 x)$ $y = cos^2 (x^2 - 3x)$ ?

1 Answer

Sep 26, 2015

$y'=(3-2x)sin2(x^2-3x)$

Explanation:

$y'=2cos(x^2-3x) * (-sin(x^2-3x)) * (2x-3)$
$y'=(3-2x)sin2(x^2-3x)$

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