Question

How do you differentiate `y = cos^2 (x^2 - 3x)`?

Answer 1

`y'=(3-2x)sin2(x^2-3x)`

Explanation:

`y'=2cos(x^2-3x) * (-sin(x^2-3x)) * (2x-3)`
`y'=(3-2x)sin2(x^2-3x)`