How do you differentiate $Y = {(cos x)}^{2} - cos x$ $Y = (cos x)^2 - cos x$ ?

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How do you differentiate $Y = {(cos x)}^{2} - cos x$ $Y = (cos x)^2 - cos x$ ?

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Answer 1 · 2018-03-13T13:52:49

$\frac{d y}{d x} = sin x - sin 2 x$ $dy/dx=sinx-sin2x$

Explanation:

$differentiate {(cos x)}^{2} using the chain rule$ $"differentiate "(cosx)^2" using the "color(blue)"chain rule"$

$Given y = f (g (x)) then$ $"Given "y=f(g(x))" then"$

$\frac{d y}{d x} = f' (g (x)) \times g' (x) \leftarrow chain rule$ $dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"$

$rArrd/dx((cosx)^2)=2cosx xxd/dx(cosx)$

$color(white)(xxxxxxxxxxxx)=-2sinxcosx=-sin2x$

$y=(cosx)^2-cosx$

$rArrdy/dx=-sin2x-(-sinx)$

$color(white)(rArrdy/dx)=sinx-sin2x$

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How do you differentiate $Y = {(cos x)}^{2} - cos x$ $Y = (cos x)^2 - cos x$ ?

1 Answer

Explanation:

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How do you differentiate Y = (cos x)^2 - cos xY=(cosx)2−cosxY = (cos x)^2 - cos x?

1 Answer

Explanation:

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How do you differentiate $Y = {(cos x)}^{2} - cos x$ $Y = (cos x)^2 - cos x$ ?