Question

How do you differentiate `y=(e^x)(lnx)`?

Answer 1

`e^x(lnx + 1/x)`

Explanation:

`y=(e^x)(lnx)`

product rule

`y'=(e^x)'(lnx) + (e^x)(lnx)'`
`=e^x(lnx) + e^x 1/x`
`=e^x(lnx + 1/x)`