How do you differentiate $y=x/(2-tanx)$ ?

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Answer 1 · 2018-03-16T18:56:33

$(2-tanx+xsec^2x)/(2-tanx)^2$

$y=x/(2-tanx)$
$color(red)(d/(dx)(u/v)=(v(du)/(dx)-u(dv)/(dx))/v^2)$
So,
$(dy)/(dx)=((2-tanx)*1-x(-sec^2x))/(2-tanx)^2=(2-tanx+xsec^2x)/(2-tanx)^2$

How do you differentiate y=x/(2-tanx)y=x/(2-tanx)?