How do you divide #(1)/(1+i)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Zor Shekhtman Jun 23, 2015 #1/2-(1/2)i# Explanation: #1/(1+i)=(1-i)/((1+i)(1-i))=(1-i)/(1-i^2)=(1-i)/(1+1)=(1-i)/2=# #=1/2 - 1/2i# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 1866 views around the world You can reuse this answer Creative Commons License