How do you divide $\frac{1 + 3 i}{2 + 2 i}$ $(1+3i )/( 2+2i)$ ?

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How do you divide $\frac{1 + 3 i}{2 + 2 i}$ $(1+3i )/( 2+2i)$ ?

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Answer 1 · 2016-05-29T23:02:32

$\frac{1 + 3 i}{2 + 2 i} = 1 + \frac{1}{2} i$ $(1+3i)/(2+2i) = 1+1/2i$

Explanation:

Multiply numerator and denominator by the Complex conjugate of the numerator first:

$\frac{1 + 3 i}{2 + 2 i} = \frac{(1 + 3 i) (2 - 2 i)}{(2 + 2 i) (2 - 2 i)} = \frac{8 + 4 i}{8} = 1 + \frac{1}{2} i$ $(1+3i)/(2+2i) = ((1+3i)(2-2i))/((2+2i)(2-2i))=(8+4i)/8 = 1+1/2i$

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How do you divide $\frac{1 + 3 i}{2 + 2 i}$ $(1+3i )/( 2+2i)$ ?

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Explanation:

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How do you divide $\frac{1 + 3 i}{2 + 2 i}$ $(1+3i )/( 2+2i)$ ?