How do you divide #(1+3i )/( 2+2i)#?
1 Answer
May 29, 2016
#(1+3i)/(2+2i) = 1+1/2i#
Explanation:
Multiply numerator and denominator by the Complex conjugate of the numerator first:
#(1+3i)/(2+2i) = ((1+3i)(2-2i))/((2+2i)(2-2i))=(8+4i)/8 = 1+1/2i#