Question

How do you divide `(1-3i)/(2-7i)`?

Answer 1

`23/53+1/53 i`

Explanation:

Given:`" " (1-3i)/(2-7i)`

Multiply by 1 in the form of: `(2+7i)/(2+7i)`

`((1-3i)(2+7i))/((2-7i)(2+7i))`

`(2+7i-6i-21i^2)/(2^2-49i^2)`

but `i^2 = -1" so "-49i^2 = +49`

`(23+i)/53 -> 23/53+1/53 i`