How do you divide #(-10-5i)/(-6+6i)#?

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Answer 1 · 2016-09-17T20:25:04

#5/12+5/4i#

#(-10-5i)/(-6+6i)#

Multiply the numerator and denominator by the conjugate of the denominator.

#(-10-5i)/(-6+6i) *(-6-6i)/(-6-6i)#

#(60+30i+60i+30i^2)/(36-36i+36i-36i^2)#

#(60+90i+30(-1))/(36-36(-1))#

#(30+90i)/72#

#(6(5+15i))/(6(12)#

#(5+15i)/12# or #5/12+5/4i#