How do you divide $(2x^2-3x)/(3x + 1)$ ?

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Answer 1 · 2015-11-13T14:43:15

$(2x^2-3x)/(3x+1) = 2/3x -11/9$ with remainder of $11/9$

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How do you divide (2x^2-3x)/(3x + 1)(2x^2-3x)/(3x + 1)?