How do you divide $\frac{2 x^{2} - 6 x + 6}{2 x - 3}$ $(2x^2-6x+6)/(2x - 3)$ ?

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How do you divide $\frac{2 x^{2} - 6 x + 6}{2 x - 3}$ $(2x^2-6x+6)/(2x - 3)$ ?

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Answer 1 · 2016-06-22T14:48:39

$x - 3 - \frac{3}{2 x - 3}$ $x-3-3/(2x-3)$

Explanation:

$(2 x^{2} - 6 x + 6) \div (2 x - 3)$ $(2x^2-6x+6)-:(2x-3)$

color(magenta)(
color(white)(
$2 x^{2} - 6 x + 6$ $" "2x^2-6x+6$
$color(magenta)(x)(2x-3) ->" "ul(2x^2-3x" ")larr" Subtract"$
$" "0color(white)(.)-6x+6$
$color(magenta)(-3)(2x-3)->" "ul(-6x+9)larr" Subtract"$
$" "0color(white)(.)color(magenta)(-3)larr" Remainder"$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$color(magenta)(x-3-) (color(magenta)(3))/(2x-3)$

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How do you divide $\frac{2 x^{2} - 6 x + 6}{2 x - 3}$ $(2x^2-6x+6)/(2x - 3)$ ?

1 Answer

Explanation:

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How do you divide (2x^2-6x+6)/(2x - 3)2x2−6x+62x−3(2x^2-6x+6)/(2x - 3)?

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Explanation:

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How do you divide $\frac{2 x^{2} - 6 x + 6}{2 x - 3}$ $(2x^2-6x+6)/(2x - 3)$ ?