How do you divide $\frac{2 x^{3} + 13 x + 15}{3 x + 12}$ $(2x^3 + 13x + 15)/(3x + 12)$ ?

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How do you divide $\frac{2 x^{3} + 13 x + 15}{3 x + 12}$ $(2x^3 + 13x + 15)/(3x + 12)$ ?

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Answer 1 · 2018-07-22T17:46:07

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$\frac{2 x^{3} + 13 x + 15}{3 x + 12} = \frac{2 x^{2}}{3} - \frac{8 x}{3} + 15 + \frac{(- 165)}{3 x + 12}$ $color(red)((2x^3+13x+15)/(3x+12)=(2x^2)/3-(8x)/3+15+((-165))/(3x+12)$

Explanation:

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Perform Polynomial Long Division:

$\frac{2 x^{3} + 13 x + 15}{3 x + 12}$ $color(blue)((2x^3+13x+15)/(3x+12)$
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How do you divide $\frac{2 x^{3} + 13 x + 15}{3 x + 12}$ $(2x^3 + 13x + 15)/(3x + 12)$ ?

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Explanation:

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How do you divide $\frac{2 x^{3} + 13 x + 15}{3 x + 12}$ $(2x^3 + 13x + 15)/(3x + 12)$ ?