How do you divide −2x3−23x2−4x+11x−5?
1 Answer
Nov 12, 2017
Explanation:
one way is to use the divisor as a factor in the numerator
consider the numerator
−2x2(x−5)−10x2−23x2−4x+11
=−2x2(x−5)−33x(x−5)−165x−4x+11
=−2x2(x−5)−33x(x−5)−169(x−5)−845+11
=−2x2(x−5)−33x(x−5)−169(x−5)−834
quotient =−2x2−33x−169, remainder =−834
⇒−2x3−23x2−4x+11x−5
=−2x3−33x−169−834x−5
