How do you divide #(-2x^3-2x^2-14x+11)/(x-5) #?

1 Answer
Tony B
May 20, 2017

#-2x^2-12x-74-359/(x-5)#

Explanation:

#" "-2x^3-color(white)(.)2x^2-14x+11#
#color(magenta)(-2x^2)(x-5)->" "ul(-2x^3+10x^2) larr" Subtract"#
#" "0color(white)(x^3)-12x^2-14x+11#
#color(magenta)(-12x)(x-5)->" "ul(-12x^2+60x) larr" Subtract"#
#" "0color(white)(.)-74x+color(white)(.)11#
#color(magenta)(-74)(x-5)->" "ul(-74x+370) larr" Subtract"#
#" "0color(magenta)(color(white)(.)-359 larr" Remainder")#

#color(magenta)(-2x^2-12x-74-359/(x-5))#

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