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How do you divide $\frac{2 x^{3} + 4 x^{2} - 4 x - 2}{x + 2}$ $(2x^3+ 4 x^2-4x-2)/(x+2)$ ?

1 Answer

Dec 20, 2015

I found: $(x + 2) (2 x^{2} - 4) + 6$ $(x+2)(2x^2-4)+6$

Explanation:

I used the division of polynomials and got:

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