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How do you divide $\frac{2 x^{3} - x^{2} - 3 x + 1}{x + 2}$ $(2x^3-x^2-3x+1)/(x+2)$ ?

1 Answer

Vinícius Ferraz

Jun 15, 2018

$2 x^{2} - 5 x - 7 + \frac{15}{x + 2}$ $2x^2 - 5x -7 + frac{15}{x + 2}$

Explanation:

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