How do you divide #(2x^3-x^2+5)÷(x-2)#?

1 Answer

Quotient = #2*x^2+3*x+6#
Remainder = #17#

Explanation:

Without omitting any degrees of the polynomial, the dividend is #2*x^3 - x^2 + 0*x + 5# and the divisor is #x - 2#
Now using the long division method step by step
Q = quotient
R = remainder
Q0 = 0
R0 = #2*x^3 - x^2 + 0*x + 5#
Q1 = #2*x^2#
R1 = #+3x^2+0*x+5#
Q2 = #2*x^2+3x#
R2 = #+6*x+5#
Q3 = #2*x^2+3*x+6#
R3 = #17#