How do you divide 2x5−3x3+2x−12−3x2+3?
1 Answer
Jul 29, 2018
Explanation:
2x5−3x3+2x−12−3x2+3
=−132x5−3x3+2x−12x2−1
=−132x5−2x3−x3+x+x−12x2−1
=−13(2x3−x)(x2−1)+x−12x2−1
=−13(2x3−x+x−12x2−1)
=−23x3+13x+x−12−3x2+3
