How do you divide #(3x^2+9x+36) / (x-3) #? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Augy Jun 13, 2018 #(3(x^2+3x+12))/(x-3)# Explanation: #(3x^2+9x+36)/(x-3)# Factorise #3x^2+9x+36# #(3(x^2+3x+12))/(x-3)# #x^2+3x+12# cannot be factorised with rational numbers Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1483 views around the world You can reuse this answer Creative Commons License